Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is none, oncePerWeek, severalPerWeek or daily.
Build a proper factor for the responses below and store it in a variable w.
Print the factor.
Write the code to count the numbers of occurrences of each level and print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek
[7] oncePerWeek <NA> none none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 × 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the results.
Next, understand why an error is generated and use replace argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor w from it.
Finally, count the numbers of occurrences of each level in w.
Ensure, that levels are in order provided in the variable lvs.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "oncePerWeek" "none" "severalPerWeek"
sample( lvs, 3 )
[1] "daily" "none" "severalPerWeek"
sample( lvs, 3 )
[1] "none" "oncePerWeek" "daily"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] daily daily oncePerWeek severalPerWeek oncePerWeek severalPerWeek
[7] severalPerWeek oncePerWeek daily daily none daily
[13] oncePerWeek severalPerWeek severalPerWeek severalPerWeek oncePerWeek daily
[19] daily none oncePerWeek oncePerWeek oncePerWeek daily
[25] daily none severalPerWeek none severalPerWeek none
[31] oncePerWeek severalPerWeek severalPerWeek severalPerWeek daily oncePerWeek
[37] oncePerWeek severalPerWeek severalPerWeek daily severalPerWeek oncePerWeek
[43] none none none severalPerWeek severalPerWeek severalPerWeek
[49] oncePerWeek severalPerWeek none daily severalPerWeek severalPerWeek
[55] none oncePerWeek none oncePerWeek daily severalPerWeek
[61] severalPerWeek severalPerWeek none severalPerWeek oncePerWeek oncePerWeek
[67] none severalPerWeek oncePerWeek oncePerWeek oncePerWeek oncePerWeek
[73] daily none daily oncePerWeek daily severalPerWeek
[79] severalPerWeek daily oncePerWeek oncePerWeek oncePerWeek severalPerWeek
[85] oncePerWeek oncePerWeek daily oncePerWeek oncePerWeek none
[91] daily none daily oncePerWeek none severalPerWeek
[97] oncePerWeek none none daily
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 × 2
f n
<fct> <int>
1 none 19
2 oncePerWeek 31
3 severalPerWeek 29
4 daily 21
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its levels.
The factor w from the previous exercise will be then shown in this order: none, oncePerWeek, severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed: daily, severalPerWeek, oncePerWeek, none.
Apply to w one of the fct_ functions from the tidyverse library to produce a factor w2 with the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 × 2
f n
<fct> <int>
1 daily 21
2 severalPerWeek 29
3 oncePerWeek 31
4 none 19